Question
In: Physics
A simple pendulum suspended in a rocket ship has a period T0. Assume that the rocket...
A simple pendulum suspended in a rocket ship has a period
T0. Assume that the rocket ship is near the earth in a
uniform gravitational field.
True False If the length of the pendulum is doubled, the
new period will be: square root of 2 times T0.
True False If the ship accelerates upward, the period
increases.
True False If the ship moves upward with a constant
velocity, the period increases.
True False If the mass of the pendulum is halved, the
period decreases.
True False If the ship accelerates downward at 9.81
m/s2, the pendulum will no longer oscillate.
Solutions
genius_generous answered 2 years agoRelated Solutions
A simple pendulum suspended in a rocket ship has a period T0. Assume that the rocket...
A simple pendulum suspended in a rocket ship has a period T0.
Assume that the rocket ship is near the earth in a uniform
gravitational field.
If the ship accelerates downward at 9.81 m/s2, the pendulum
will no longer oscillate.
If the length of the pendulum is doubled, the new period will
be: square root of 2 times T0.
If the ship moves upward with a constant velocity, the period
increases.
If the ship accelerates upward, the period increases.
If...
SIMPLE PENDULUM 1. What are the factors affecting the period of a simple pendulum? 1.1. What...
SIMPLE PENDULUM
1. What are the factors affecting the period of a simple
pendulum?
1.1. What must you do to the length of a simple pendulum so that
its period is doubled?
1.2. Determine the acceleration due to gravity in a location
where a simple pendulum is 150.0 cm long makes 100 vibrations in
246 s.
1.3 What can you conclude from the graph? (Chegg on my laptop
wouldn't let me upload so I've attached the link) -
http://tinypic.com/r/j6o5qq/9
A) Write the Lagrangian for a simple pendulum consisting of a point mass m suspended at...
A) Write the Lagrangian for a simple pendulum consisting of a
point mass m suspended at the end of a massless string of length l.
Derive the equation of motion from the Euler-Lagrange equation, and
solve for the motion in the small angle approximation. B) Assume
the massless string can stretch with a restoring force F = -k
(r-r0), where r0 is the unstretched length. Write the new
Lagrangian and find the equations of motion. C) Can you re-write
the...
A simple pendulum may be described ideally as a point mass suspended by a massless string...
A simple pendulum may
be described ideally as a point mass suspended by a massless string
from some point about which it is allowed to swing back and forth
in a place. A simple pendulum can be approximated by a small metal
sphere which has a small radius and a large mass when compared
relatively to the length and mass of the light string from which it
is suspended. If a pendulum is set in motion so that is swings...
12. A simple pendulum is made of a hollow spherical bob full of mercury and suspended...
12. A simple pendulum is made of a
hollow spherical bob full of mercury and suspended by a thin
string. If the mercury begins to leak from the small hole at its
bottom, then its time period:
(a)
Increases.
(b) Decreases.
(c)First increases and then decreases
till it is the same again
(d) First decreases and then increase
still it is the same again
A simple pendulum consists of a particle of mass m suspended by a long, massless wire...
A simple pendulum consists of a particle of mass m suspended by
a long, massless wire of length L. Draw a free body diagram for the
pendulum bob corresponding to a moment when the bob is located an
angular displacement Φ away from (eg. to the right of) equilibrium.
Determine an expression in terms of m, g, and Φ for the component
of the net force on the bob that points tangent to the path of the
bob.
Assume that...
on another planet a simple pendulum has a length of 90.0 cm oscillates with a period...
on
another planet a simple pendulum has a length of 90.0 cm oscillates
with a period of 1.7 seconds.
1. compute the planet’s accerleration due to gravity and
comment on the planet’s gravity as compared to Earth’s
gravity.
2. on this same planet. what would be the period of
oscillation if the pendulum had a length of exactly 2.00
meters?
Why is mass not a factor in the equation for the period of a simple pendulum?
Why is mass not a factor in the equation for the period of a
simple pendulum?
A simple pendulum consists of a small object of mass m= 0.150 kg suspended from a...
A simple pendulum consists of a small object of mass m= 0.150 kg
suspended from a support stand by a light string. The string has a
length L= 0.750 m. The string has an initial position given by θ=
65.0° relative to the vertical. The pendulum is released from rest.
Air resistance is negligible during the subsequent motion of the
pendulum.
a)Calculate the work done by gravity on the pendulum as it moves
from its initial position to the lowest...
Suppose a particular simple pendulum of length l_0 has a period of T_0 for small oscillations...
Suppose a particular simple pendulum of length l_0 has a period
of T_0 for small oscillations here on Earth.
(a) Suppose the original pendulum is set up with the same length
l_0 on the surface of a new planet, Uzaz, and it oscillates with a
period 5/4 as long as the period of Earth. Given the gravitational
acceleration here on Earth is 9.8 m/s^2, what is the gravitational
acceleration (g)(v) at the surface on Uzaz?
(b) If the radius of...
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