A 0.5566-g sample containing CuCl2 . 2H2O (MW = 170.47) was dissolved in 25.00 mL of...

A 0.5566-g sample containing CuCl₂ . 2H₂O (MW = 170.47) was dissolved in 25.00 mL of water. About 25.00 mL of a 10% aqueaous solution of thioacetamide was added to the solution and heated. The black CuS precipitate formed upon heating the solution was filtered, dried, and weighed. If the precipitate was found to weigh 0.2074 g, calulate the percentage of CuCl₂ . 2H₂O in the sample.

Expert Solution

given sample wt = 0.5566g

after treatment with thioacetamide black CuS is ppted, &found 0.2074g

% yield = amount produced exptlly / amount for 100% yield * 100

= 0.2074 /0.5566 * 100

= 37.26%

thank u

queen_honey_blossom answered 2 years ago

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