Question

Refer to HW#9.45 to match the following:

-       A.       B.       C.       D.    # of lone pairs in ICl Read Answer Items for Question 15       -       A.       B.       C.       D.    # of single bonds in H2S Read Answer Items for Question 15       -       A.       B.       C.       D.    # of single bond(s) in N2H4 Read Answer Items for Question 15       -       A.       B.       C.       D.    # of double bond(s) in COBr2 Read Answer Items for Question 15

Answer A. 1 B. 2 C. 5 D. 6

Answer 1

In ICl molecule each atom that is iodine and chlorine have seven valence electrons, they form a single bond by sharing one electron each to acquire a noble gas structure. Their Lewis structure can be drawn as follows:

Therefore, ICl has six lone pairs of electrons.

Hence, the correct option is D.

In H₂S molecule sulfur atom is attached to the two hydrogen atoms by single bonds, each hydrogen atom shares one electron and the sulfur atom shares two electrons to form two single bonds with the two hydrogen atoms to acquire a noble gas structure.. The structure of H₂S molecule is shown below:

Therefore, the number of single bonds in H₂S is two.

Hence, the correct option is B.

In N₂H₄ molecule each nitrogen atom shares one electron with each other and two electrons with two hydrogen atoms to acquire a noble gas structure.. Each nitrogen atom is attached two hydrogen atoms with single bonds and the two nitrogen atoms are also linked to each other by a single bond thus, a total of five single bonds are formed. The Lewis structure of N₂H₄ molecule is shown below:

Therefore, in N₂H₄ there are five single bonds.

Hence, the correct option is C.

In COBr₂ molecule, the carbon atom has four, the oxygen atom has six and the bromine atom has seven valence electrons. The Lewis structure COBr₂ molecule can be drawn as follows:

Therefore, in COBr₂ molecule there is nnly one double bond.

Hence, the correct option is A.