Question

In: Chemistry

A solution is prepared by dissolving 12.36 g of CaCl2 ( an electrolyte, molar mass= 111g)...

A solution is prepared by dissolving 12.36 g of CaCl2 ( an electrolyte, molar mass= 111g) in 135g of H2O ( molar mass =18.0g). The resulting solution has a density of 1.10 g/ml. Calculate the molarity of CaCl2 in the solution.

Solutions

Expert Solution

Total mass = 12.36 g + 135 g = 147.36 g

density = mass / volume
1.10 g/ml = 147.36 / volume
volume = 134 mL
                 = 0.134 L


mass of CaCl2 = 12.36 g
Molar mass of CaCl2 = 111 g
number of moles of CaCl2 = mass / molar mass
                                                      = 12.36/111
                                                      = 0.114 mol

V = 0.134 L

M = number of moles / volume
     = 0.114 / 0.134
     = 0.83 M

Answer: 0.83 M


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