Chlorophyll is known to have its absorption maximum at 680 nm (red light) with the extinction...

Chlorophyll is known to have its absorption maximum at 680 nm (red light) with the extinction coefficient of 105 L/mol*cm. Assume a plant with leaves about 0.6 mm thick with the chlorophyll concentration of 0.0005 mol/L. How much red light in [%] will pass through a typical leave? Select one: a. 0.1 b. 10 c. 0.01 d. 0.3 e. 1

Expert Solution

The Beer-Lambert law is an empirical relationship in relating the absorption of light to the amount of chemical when light is traveling through the sample. The Beer´s law states that absorbance (A) is proportional to the concentration (C) of the light-absorbing chemicals in the sample according to the following

A = E . l . C

Where E = molar absorptivity (L/mol.cm), l = length of light path in a sample cell, and C = concentration of the chemical (mol/L)

Transmittance (T) is used, which is defined as the fraction of the original ligth that has passed through the sample.

Absorbance and transmittance are related by A = -log₁₀T and T = 10^-A

The extinction coefficient is equal to the molar absortivity of leaf = 105 L/mol*cm

The thick of leaf is equal to the length of light path in a sample cell = 0.6mm = 0.06cm

The clorophyll concentration is equal to the oncentration of the chemical = 0.0005 mol/L

Then, substituting the values in the Beer-Lambert law equation:

A = 105 L/mol*cm x 0.06cm x 0.0005 mol/L

A = 0.00315

If you want to know " How much red light in [%] will pass through a typical leave?" you need to calculate the value of transmittance, with the following equation:

T = 10^-A = 10^-0.00315 = 0.9928 which is equal in percentage %T = 99.28

Considering the answer choices (a, b, c, d, e) it seems that the question should be relates to How much red light in [%] will NOT pass through a typical leave?

It is recommended to check the correct data of the question

queen_honey_blossom answered 2 years ago

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