a 3 m long beam with a mass of 35 is balanced horizontally on a fulcrum...

a 3 m long beam with a mass of 35 is balanced horizontally on a fulcrum (pivot) while a person stands at one end of the beam. the position of the fulcrum is .65 m from the end of the beam where the person is standing. what is the mass of the person?

Expert Solution

Center of gravity point from one end of the beam R = 3 m / 2= 1.5 m

Mass of the beam M = 35 kg

Center of gravity point from pivot point r = 1.5 m -0.65 m

= 0.85 m

Mass of person m = ?

Distance of the mass from pivot point r ' = 0.65 m

We know Mg (r) = mg(r ')

Mr = m r '

m = Mr / r '

= 35(0.85)/(0.65)

= 45.76 kg

genius_generous answered 2 years ago

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