Question

In: Physics

The weight of a metal bracelet is measured to be 0.12200 N in air and 0.07800...

The weight of a metal bracelet is measured to be 0.12200 N in air and 0.07800 N when immersed in water. Find its density.

Solutions

Expert Solution

The buoyancy force     = (0.12200 N - 0.07800 N)

                                        = 0.04400 N.

So Weight of Water displaced = 0.04400/9.8                    ( F = ma and a = gravity of Earth )

                                                       = 0.00449 Kg

Vollume of Water displaced     = 0.00449/ 1000

                                                       = 4.49 * 10-6 m3

Vollume of Water displaced = Vollume of metal bracelet

Mass of Bracelet = 0.12200 / 9.8 Kg

Density                 = Mass / Vollume

                              = 0.12200 / (9.8 * 4.49 *10-6 )

                              = 2.7726 * 103 Kg/m3

or                           = 2772.6 Kg/m3


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