In: Statistics and Probability
As part of an air pollution study, visibility in air was measured in three months at two altitude level.
Altitude (m) |
Visibility in town air (km) |
||
Jan |
Jun |
Dec |
|
0 |
13.5 |
3.8 |
14.3 |
0 |
17.2 |
3.3 |
16.9 |
0 |
18.1 |
7.2 |
21.0 |
0 |
14.3 |
10.5 |
19.7 |
0 |
19.5 |
9.1 |
18.0 |
50 |
14.5 |
2.8 |
16.5 |
50 |
17.4 |
3.1 |
16.8 |
50 |
19.1 |
4.2 |
21.6 |
50 |
20.3 |
6.5 |
19.2 |
50 |
18.5 |
9.1 |
17.0 |
Question 11
Given that the data neither follow normal distribution nor have equal variance, what is the appropriate test to determine if visibility varied with different months and altitude.
Select one:
a. Kruskal-Wallis Test
b. Two independent sample t test
c. Two-way ANOVA
d. Scheirer-Ray-Hare Test
Question 12
What are the degree of freedom for the altitude, month and error (Within) respectively?
Select one:
a. 1, 2, 2
b. 1, 2, 24
c. 1, 2, 4
d. 2, 3, 5
e. 2, 3, 29
Question 13
What is the conclusion for the variable altitude?
Select one:
a. Air visibility is unequal between different heights (calculated statistics = 0.015, p-value < 0.001)
b. Air visibility is equal between different heights (calculated statistics = 0.001, p-value > 0.05)
c. Air visibility is unequal between different heights (calculated statistics = 0.004, p-value < 0.05)
d. Air visibility is equal between different heights (calculated statistics = 0.015, p-value > 0.05)
Question 14
What is the conclusion for the variable Month?
Select one:
a. Air visibility is unequal among different months (calculated statistics = 9.72, 0.001 < p-value < 0.01)
b. Air visibility is unequal among different months (calculated statistics = 9.72, p-value < 0.001)
c. Air visibility is unequal among different months (calculated statistics = 25.98, p-value < 0.001)
d. Air visibility is equal among different months (calculated statistics = 25.98, p-value > 0.05)
Question 15
What is the conclusion for the interaction effect between altitude and Month?
Select one:
a. Interaction effect exists between altitude and Month (calculated statistics = 0.75, p-value < 0.05)
b. Interaction effect exists between altitude and Month (calculated statistics = 0.75, p-value < 0.01)
c. No interaction effect between altitude and Month (calculated statistics = 0.28, 0.05 < p-value < 0.1)
d. No interaction effect between altitude and Month (calculated statistics = 0.28, 0.75 < p-value < 0.90)
using excel>data>data analysis >two way ANOVA
we have
Anova: Two-Factor With Replication | ||||||
SUMMARY | Jan | Jun | Dec | Total | ||
0 | ||||||
Count | 5 | 5 | 5 | 15 | ||
Sum | 82.6 | 33.9 | 89.9 | 206.4 | ||
Average | 16.52 | 6.78 | 17.98 | 13.76 | ||
Variance | 6.472 | 10.097 | 6.697 | 33.12829 | ||
50 | ||||||
Count | 5 | 5 | 5 | 15 | ||
Sum | 89.8 | 25.7 | 91.1 | 206.6 | ||
Average | 17.96 | 5.14 | 18.22 | 13.77333 | ||
Variance | 4.838 | 7.013 | 4.712 | 44.67352 | ||
Total | ||||||
Count | 10 | 10 | 10 | |||
Sum | 172.4 | 59.6 | 181 | |||
Average | 17.24 | 5.96 | 18.1 | |||
Variance | 5.602667 | 8.351556 | 5.086667 | |||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
altitude | 0.001333 | 1 | 0.001333 | 0.000201 | 0.98881 | 4.259677 |
Month | 917.8587 | 2 | 458.9293 | 25.98 | 1.1E-10 | 3.402826 |
Interaction | 12.05067 | 2 | 6.025333 | 0.28 | 0.416866 | 3.402826 |
Within | 159.316 | 24 | 6.638167 | |||
Total | 1089.227 | 29 |
Ans 11) here option c is true
c. Two-way ANOVA
Ans 12option b is true
b. 1, 2, 24
Ans 13 ) option b is true
b. Air visibility is equal between different heights (calculated statistics = 0.001, p-value > 0.05)
Ans 14 option c is true
c. Air visibility is unequal among different months (calculated statistics = 25.98, p-value < 0.001)
Ans 15 d is true
d. No interaction effect between altitude and Month (calculated statistics = 0.28, 0.75 < p-value < 0.90)