Question

In: Statistics and Probability

As part of an air pollution study, visibility in air was measured in three months at...

As part of an air pollution study, visibility in air was measured in three months at two altitude level.

Altitude (m)

Visibility in town air (km)

Jan

Jun

Dec

0

13.5

3.8

14.3

0

17.2

3.3

16.9

0

18.1

7.2

21.0

0

14.3

10.5

19.7

0

19.5

9.1

18.0

50

14.5

2.8

16.5

50

17.4

3.1

16.8

50

19.1

4.2

21.6

50

20.3

6.5

19.2

50

18.5

9.1

17.0

Question 11

Given that the data neither follow normal distribution nor have equal variance, what is the appropriate test to determine if visibility varied with different months and altitude.

Select one:

a. Kruskal-Wallis Test

b. Two independent sample t test

c. Two-way ANOVA

d. Scheirer-Ray-Hare Test

Question 12

What are the degree of freedom for the altitude, month and error (Within) respectively?

Select one:

a. 1, 2, 2

b. 1, 2, 24

c. 1, 2, 4

d. 2, 3, 5

e. 2, 3, 29

Question 13

What is the conclusion for the variable altitude?

Select one:

a. Air visibility is unequal between different heights (calculated statistics = 0.015, p-value < 0.001)

b. Air visibility is equal between different heights (calculated statistics = 0.001, p-value > 0.05)

c. Air visibility is unequal between different heights (calculated statistics = 0.004, p-value < 0.05)

d. Air visibility is equal between different heights (calculated statistics = 0.015, p-value > 0.05)

Question 14

What is the conclusion for the variable Month?

Select one:

a. Air visibility is unequal among different months (calculated statistics = 9.72, 0.001 < p-value < 0.01)

b. Air visibility is unequal among different months (calculated statistics = 9.72, p-value < 0.001)

c. Air visibility is unequal among different months (calculated statistics = 25.98, p-value < 0.001)

d. Air visibility is equal among different months (calculated statistics = 25.98, p-value > 0.05)

Question 15

What is the conclusion for the interaction effect between altitude and Month?

Select one:

a. Interaction effect exists between altitude and Month (calculated statistics = 0.75, p-value < 0.05)

b. Interaction effect exists between altitude and Month (calculated statistics = 0.75, p-value < 0.01)

c. No interaction effect between altitude and Month (calculated statistics = 0.28, 0.05 < p-value < 0.1)

d. No interaction effect between altitude and Month (calculated statistics = 0.28, 0.75 < p-value < 0.90)

Solutions

Expert Solution

using excel>data>data analysis >two way ANOVA

we have

Anova: Two-Factor With Replication
SUMMARY Jan Jun Dec Total
0
Count 5 5 5 15
Sum 82.6 33.9 89.9 206.4
Average 16.52 6.78 17.98 13.76
Variance 6.472 10.097 6.697 33.12829
50
Count 5 5 5 15
Sum 89.8 25.7 91.1 206.6
Average 17.96 5.14 18.22 13.77333
Variance 4.838 7.013 4.712 44.67352
Total
Count 10 10 10
Sum 172.4 59.6 181
Average 17.24 5.96 18.1
Variance 5.602667 8.351556 5.086667
ANOVA
Source of Variation SS df MS F P-value F crit
altitude 0.001333 1 0.001333 0.000201 0.98881 4.259677
Month 917.8587 2 458.9293 25.98 1.1E-10 3.402826
Interaction 12.05067 2 6.025333 0.28 0.416866 3.402826
Within 159.316 24 6.638167
Total 1089.227 29

Ans 11) here option c is true

c. Two-way ANOVA

Ans 12option b is true

b. 1, 2, 24

Ans 13 ) option b is true

b. Air visibility is equal between different heights (calculated statistics = 0.001, p-value > 0.05)

Ans  14 option c is true

c. Air visibility is unequal among different months (calculated statistics = 25.98, p-value < 0.001)

Ans 15 d is true

d. No interaction effect between altitude and Month (calculated statistics = 0.28, 0.75 < p-value < 0.90)


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