In: Statistics and Probability
Many retail stores offer their own credit cards. At the time of the credit application, the customer is given a 10% discount on the purchase. The time required for the credit application process follows a uniform distribution with the times ranging from 4 minutes to 10 minutes. |
a. | What is the mean time for the application process? |
Mean |
b. | What is the standard deviation of the process time? (Round your answer to 3 decimal places.) |
Standard deviation |
c. |
What is the likelihood a particular application will take less than 6 minutes? (Round your answer to 4 decimal places.) |
Probability |
d. |
What is the likelihood an application will take more than 5 minutes? (Round your answer to 4 decimal places.) |
Probability |
Answer :
given data :-
the customer is given a discount on the purchase =10%
uniform distribution with the times ranging from 4 minutes to 10 minutes.
let we take
a = 4
b = 10
(a). the mean time for the application process
the mean time of any uniform distribution is the midpoint between the points a and b,
here its = ( b+a )/2
= (10+4)/2
= 7
(b). the standard deviation of the process time
the variance of a uniform dist is (b-a)^2 / 12 and the s.d is the square root of the variance therefore (b-a)/sqrt(12)
= (10-4)/sqrt(12)
= 6/3.464
= 1.73
(c).the likelihood a particular application will take less than 6 minutes
this would be the area under the graph before 6. in other words,
the area of the rectangle whose base is from 4 to 6 and height is = 1/6
= 0.166
= 16.66%
(d). the likelihood an application will take more than 5 minutes
this is the area under the graph after 5,
area of a rectangle whose base is between 5 and 10, and height is 1/6