Question

K.Brew sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet. Random samples of sales receipts were studied for mail-order sales and internet sales, with the total purchase being recorded for each sale. A random sample of 14 sales receipts for mail-order sales results in a mean sale amount of $80.40 with a standard deviation of $24.75. A random sample of 10 sales receipts for internet sales results in a mean sale amount of $66.30 with a standard deviation of $15.75. Using this data, find the 98% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases. Assume that the population variances are not equal and that the two populations are normally distributed.

Step 2 of 3 :  

Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places

Step 3 of 3:

Construct the 98%

confidence interval. Round your answers to two decimal places

Answer 1

margin of error=2.508*8.913

22.353804

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