Question

You have 11m of 0.60mm diameter copper wire and a power supply capable of passing 25Athrough the wire.

Part A

What magnetic field strength would you obtain inside a 2.0-cm-diameter solenoid with the wire spaced as closely as possible?

Part B

What magnetic field strength would you obtain at the center of a single circular loop made from the wire?

Answer 1

The number s of turns in the soleniod is

        N = 11m / 2 ?r

here r = 0.01m

      N = 11m / 2 ? (0.01)

          = 175 turns

Length of the soleniod is L = (0.6x10^-3)(175)

                                         = 0.105m

The magnetic field strength is

          B =?_o N I / L

           = ( 4?x10^-7) (175)(25) / 0.105

           = 0.0524T

  

Magnetic field at the center of a single coil is

        B =?_o I / 2 ? r

Here 2 ? r = 11m

          =(4?x10^-7)(25) / 11

          =2.86x10^-6 T