In: Physics
1.
Given lengthof the copper wire l = 5 km = 5*10^3 m,
resistivity of copper is rho = 1.68*10^-8 ohm m
diameter of the wire is d= 4mm, r = 2mm= 2*10^-3 m
from the relation between R, rho,A,l i
R = rho*l/A
R =
(1.68*10^-8*5*10^3)/(pi(2*10^-3)^2) ohm
R = 6.6845076098596 ohm
= 6.7 ohm
answer is option d---------------------> Answer
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2.
capacitance of each capacitor C = 4 mF = 4*10^-3
F, battery of V = 12 V
three capacitors are connected in series then net capacitance is Cn = C/3 = 4*10^-3 /3 =1.33 mF
from the relation Q = C*V ==> Q = 1.33*10^-3*12 C = 15.96 mC = 16 mC ------------>> anaswer --B
3
energy stored in the capacitor is U = 1/2 c* v^2 = 0.5*1.33*10^-3*12^2 J
U = 0.09576
J
U = 95.76
mJ
U = 96 mJ
<<<-------------- answer --D