In: Statistics and Probability
The final exam grade of a mathematics class has a normal distribution with mean of 81 and standard deviation of 6.6. If a random sample of 40 students selected from this class, then what is the probability that the average final exam grade of this sample is between 77 and 82? Answer: (keep 4 decimal places)
Solution :
Given that,
mean = = 81
standard deviation = = 6.6
n = 40
=81
= / n = 6.6 40 = 1.0435
P (77 < < 82)
P ( 77 - 81 / 1.0435) < ( - / ) < ( 82 - 81 / 1.0435)
P ( - 4 / 1.0435 < z < 1 / 1.0435 )
P (-3.83 < z < 0.96)
P ( z < - 0.259 ) - P ( z < -3.83)
Using z table
= 0.8315 - 0.0001
= 0.8314
Probability = 0.8314