Suppose that z = xy, where x and y are independent and normally distributed random variables

Suppose that z = xy, where x and y are independent and normally distributed random variables. The mean and variance of x are µ_x = 10 and σ²_x = 2. The mean and variance of y are µ_y = 15 and σ²_y = 3. Find the mean and variance of z by simulation. Does µz = µ_xµ_y? Does σ²_z = σ²_x σ²_y? Do this for 100, 1000, and 5000 trials.

Solutions

Expert Solution

Two normally distributed variables x and y are given with their mean and variance. For x, mean µx = 10 and variance is σ2x = 2. And for y, mean is µy = 15 and variance is σ2y = 3. Here, one need to simulate the two variables and generate new variable by the equation z = xy.

Once the new variable is generated, one needs to verify that if the mean of new variable generated is equal to the sum of the means of variable x, y and the variance of new variable is equal to the sum of variance of x, y.

In MATLAB, function ‘randn(m,n)’ generates normally distributed pseudorandom numbers matrix m by n with mean of zero with standard deviation of 1. To generate a new variable with standard deviation and a mean of use the following equation.

σy + µ, where y is the generated random numbers.

MATLAB code:

MATLAB Output:

From the results obtained, one can see that mean of variable z is the product of mean of variables x, y but the variance of z is not equal to product of variance of x, y.

The simulated results are summarized in the following table.

From the results obtained, one can see that mean of variable z is the product of mean of variables x, y but the variance of z is not equal to product of variance of x, y.

Junaid answered 2 years ago

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