y'''-2y"-y'+2y=xex^2+2x a) Find a general solution to the corresponding homogeneous equation, given that e2x is one....

y'''-2y"-y'+2y=xe^{x^2+2x}

a) Find a general solution to the corresponding homogeneous equation, given that e^2x is one.

b) In the method of variation of parameters, find v₁, where v₁e^2x + v₂y₂ + v₃y₃ = y_p is a particular solution to the inhomogeneous equation. Use the method of variation of parameters

Please explain and show work, thanks!

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Colby Messinger answered 1 year ago

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