A rock is thrown downward from a tower with an initial speed of 32.2 m/s. If...

A rock is thrown downward from a tower with an initial speed of 32.2 m/s. If it hits the ground in under 2 seconds how high is the tower?

Expert Solution

We have the equation of motion

Where, S is displacement, u is initial velocity, a is acceleration and t is time of motion.

For the given problem,

initial speed of the rock (u) = 32.2 m/s

acceleration of the rock (a) = acceleration due to gravity= 9.8 m/s²

time of motion = 2 s

Putting these values in the equation of motion,

Hence, the height of the tower is 84 m.

For any doubt please comment.

genius_generous answered 3 weeks ago

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