In: Statistics and Probability
Two groups are having competition for chase. If one plays it in its own campus it will win with probability P> ½. They will play three times, two in group 1’s campus and one in group 2’s campus. If one wins game 1 and 2, then game 3 is not going to be played. a) What is P[T], the probability that the group 1 wins the series? b) If they play only once will group 1 have higher chance of winning than from playing 3 games?
Given,
Two groups are having competition for chase. If one plays it in its own campus it will win with probability P > ½.
Probability of Group 1 winning in its own campus = P
Probability of Group 2 winning in Group 1’s campus or Group 1 losing in its own campus = 1 - P
Probability of Group 1 winning in Group 2’s Campus = 1 – P
Answer to 1st Question
:
There are 2 cases –
· Case I: Group 1 winning both the games in its own campus
Probability of Group 1 winning both the games in its own campus = P^2
· Case II: Group 1 losing one of the two games in its own campus and winning the third one in Group 2’s campus
Probability of Group 1 winning 1 and losing 1 game = (2C1)xPx(1 - P) = 2P(1 - P)
Probability of Group 1 winning in Group 2’s Campus = 1 – P
The required Probability = 2P(1 - P)(1 - P) = 2P{(1 - P)}^2
Therefore,
Total Probability of Group 1 winning the series, P(T) = (P^2) + 2P{(1 - P)}^2
Answer to 2nd
Question:
Since, it is already given, P >
½
Let P = 0.6
If 3 games are played, P(T) = (P^2) + 2P{(1 - P)}^2 = 0.552
Which states that there is 55% chance of Group 1 winning if 3 games are played
If only 1 game is played, there will be two cases –
· Case I: If the game is played in Group 1’s campus
Probability of Group 1 winning = P = 0.6
That is, there is 60% chance of Group 1 winning.
· Case II: If the game is played in Group 2’s campus
Probability of Group 1 winning = 1 - P = 0.4
That is, there is 40% chance of Group 1 winning.
Hence, the chance of winning of Group 1 depends on which campus they are playing
If they are playing in their own campus then they have a better chance of winning then they playing all three games.