In: Statistics and Probability
You may need to use the appropriate technology to answer this question.
A standardized exam consists of three parts: math, writing, and critical reading. Sample data showing the math and writing scores for a sample of 12 students who took the exam follow.
Student | Math | Writing |
---|---|---|
1 | 540 | 474 |
2 | 432 | 374 |
3 | 528 | 463 |
4 | 574 | 612 |
5 | 448 | 420 |
6 | 502 | 520 |
7 | 480 | 430 |
8 | 499 | 459 |
9 | 610 | 615 |
10 | 572 | 541 |
11 | 390 | 335 |
12 | 593 | 613 |
(a)
Use a 0.05 level of significance and test for a difference between the population mean for the math scores and the population mean for the writing scores. (Use math score − writing score.)
Formulate the hypotheses.
H0: μd = 0
Ha: μd ≠ 0 CORRECT!!
Calculate the test statistic. (Round your answer to three decimal places.)
Calculate the p-value. (Round your answer to four decimal places.)
p-value =
(b) What is the point estimate of the difference between the mean scores for the two tests? (Use math score − writing score.)
Using Minitab<stats<basic Statistics<paired t test
Here is the output:
Paired T-Test and CI: Math, Writing
Descriptive Statistics
Sample | N | Mean | StDev | SE Mean |
Math | 12 | 514.0 | 68.3 | 19.7 |
Writing | 12 | 488.0 | 93.9 | 27.1 |
Estimation for Paired Difference
Mean | StDev | SE Mean | 95% CI for μ_difference |
26.0 | 36.8 | 10.6 | (2.6, 49.4) |
µ_difference: mean of (Math - Writing)
Test
Null hypothesis | H₀: μ_difference = 0 |
Alternative hypothesis | H₁: μ_difference ≠ 0 |
T-Value | P-Value |
2.448 | 0.032 |
Test Staistic=2.448
P value= 0.032
b) Point Estimate =math score − writing score.=514-488=26
Student | Math | Writing | d |
1 | 540 | 474 | 66 |
2 | 432 | 374 | 58 |
3 | 528 | 463 | 65 |
4 | 574 | 612 | -38 |
5 | 448 | 420 | 28 |
6 | 502 | 520 | -18 |
7 | 480 | 430 | 50 |
8 | 499 | 459 | 40 |
9 | 610 | 615 | -5 |
10 | 572 | 541 | 31 |
11 | 390 | 335 | 55 |
12 | 593 | 613 | -20 |
d-bar | 26 |
Please do the comment for any doubt or clarification. Thank You!