In: Statistics and Probability
Residents of neighboring towns in a state have an ongoing disagreement over who lays claim to the higher average price of a single-family home. A person in one of these towns obtains a random sample of homes listed for sale with a major local realtor to investigate if there is actually any difference in the average home price. Complete parts a through e.
Town 1 | Town 2 |
389900 | 489000 |
415000 | 589000 |
489900 | 599900 |
699000 | 769000 |
759000 | 980000 |
809900 | 1099000 |
985000 | 1188000 |
1179000 | 1365000 |
1465000 | 1655000 |
1499000 | 1960000 |
1585000 | 1996800 |
1640000 | 2185000 |
1799000 | 2550000 |
1865000 | 2930000 |
2485000 | 2979900 |
2585000 | 3195000 |
3775000 | 3375000 |
4145000 | 3445000 |
4850000 | 3650000 |
5600000 | 4595000 |
5969000 |
5800000 |
c) Test the hypothesis and find the P-value.
Find the test statistic.
t=___
Find the P-value.
P=___
d) What is your conclusion? Use
alphaα=0.05.
e) Use the pooled t-test to test the hypothesis and compare your answer to parts c and d.
Using the data provided, check the assumptions and conditions for this test. Which of the following assumptions or conditions are satisfied for the given data? Select all that apply.
A. Nearly normal condition
B. Independence assumption
C. Equal variance assumption
D. Independent group assumption
Find the test statistic of the pooled t-test.
t=___ (Round to two decimal places as needed.)
Find the P-value of the pooled t-test.
P=____ (Round to three decimal places as needed.)
What is your conclusion of the pooled t-test? Use
alpha=0.05.
How do your answers to parts c and d compare to your answer in part e?
Using Excel<data<megastat<Hypothesis Test<Paired Observations
Hypothesis Test: Independent Groups (t-test, pooled variance) | ||||
Town 1 | Town 2 | |||
21,42,319.05 | 22,56,933.33 | mean | ||
17,23,009.35 | 14,29,402.11 | std. dev. | ||
21 | 21 | n | ||
40 | df | |||
-1,14,614.286 | difference (Town 1 - Town 2) | |||
25,05,97,57,96,476.190 | pooled variance | |||
15,83,027.415 | pooled std. dev. | |||
4,88,532.866 | standard error of difference | |||
0 | hypothesized difference | |||
-0.235 | t | |||
.8157 | p-value (two-tailed) | |||
-11,01,976.039 | confidence interval 95.% lower | |||
8,72,747.468 | confidence interval 95.% upper | |||
9,87,361.754 | margin of error |
c) Test the hypothesis and find the P-value.
Find the test statistic.
t= -0.235
Find the P-value.
P= 0.8157
d) What is your conclusion? Use
alphaα=0.05.
Since p-value is greater than 0.05(alpha). We fail to reject H0. The mean prices are not significantly different.
e) OPTION A,B,C
t= -0.235
p= 0.8157
Conclusion
Same