Question

a.) In families of 4 offspring, what is the probability of finding the oldest and youngest offspring to both be female?

(As you calculate your response, keep variable rounded at 4 decimal places, provide your answer as a percentage with 2 decimal places, no percentage sign needed(%) i.e., 45.21)

b.) Chestnut, Palomino, and Cremello coat coloring is horses is determined by a partial or incomplete dominant mode of inheritance. Chestnut (CC) and cremello (C^CrC^Cr)

animals have a homozygous genotype, and palomino coat coloring is a result from a heterozygous genotype (CC^Cr)

Two palomino horses have created 3 offspring. What is the chance that these 3 offspring result in 1 of each color (1 chestnut, 1 cremello, and 1 palomino) colts?

(As you calculate your response, keep variable rounded at 4 decimal places, provide your answer as a percentage with 2 decimal places, no percentage sign needed(%)i.e., 45.21)

Answer 1

a) The total number of possibilities for the 4 offsprings to be either male or female is

= 2 * 2 * 2 * 2 = 16

The total number of cases in which the youngest and the oldest offspring is female is

= 1 * 2 * 2 * 1 = 4

The probability of finding the oldest and the youngest offsprings to both be female is

= 4/16 = 1/4

The required percentage is = 1/4 * 100 = 25 (answer)

b) The genotype of a Palomino horse is .

The 4 possible genotypes for the offsprings of two Palomino horses are

i)   - Chestnut

ii) - Palomino

iii) - Palomino

iv) - Cremello

The probability that an offspring will be Chesnut is = 1/4

The probability that an offspring will be Palomino is = 2/4

The probability that an offspring will be Cremello is = 1/4

The probability that the 3 offsprings result in 1 of each color is

The required percentage is = 18.75

Thank You!! Please Upvote!!