In: Statistics and Probability
The average number of gallons of lemonade sold during a baseball game is 20, with a standard deviation of 3 gallons. Assume the amount of lemonade sold is normally distributed. When a game is played, find the probability that the amount of lemonade sold is:
A) If 10 games are played, find the probability that the mean amount of lemonade sold is less than 19 gallons
Solution :
Given that ,
mean = = 20
standard deviation = = 3
P( < 19 ) = P(( - ) / < (19 -20) /3 )
= P(z < -0.33 )
= 0.3707
probability = 0.3707
A) n = 10
= = 20
= / n = 3 / 10 = 0.9487
P( < 19 ) = P(( - ) / < (19-20) /0.9487 )
= P(z < -1.05 )
= 0.1469
probability =0.1469