Question

In: Physics

In his double-slit experiment with electrons, jonsson used electrons with kinetic energy 50 kev. A) Find...

In his double-slit experiment with electrons, jonsson used electrons with kinetic energy 50 kev.

A) Find the electron's de Broglie wavelength

B) The two slits were separated by 2.0 um. On a screen 0.350m from the slits, what was the distance between bright diffraction fringes?

Expert Solution

The momentum of the electron in terms of kinetic energy is,

Here, m is the mass of the electron and K is the kinetic energy of the electron.

The wavelength of the electron accroding to De Broglie's concept is,

Here, h is the Planck's constant.

Then,

Therefore, the wavelength of the electron is or approximately 5.5 pm.

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(b) The distance between the bright fringes is given as follows:

Here, m is order of the spectrum, l is the distance between the slits and the screen, and d is the distance

between the slits.

Then,

Therefore, the distnace between the bright diffraction fringes is .

genius_generous answered 1 hour ago

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