In: Chemistry
What is the pH when 125 mL of 0.1 M NaOH is added to 175 mL of 0.2 M CH3COOH (acetic acid) if pKa for acetic acid = 4.76?
Number of moles of NaOH = 125/1000 * 0.1M = 12.5m moles
Number of moles of CH3COOh = 175/1000 * 0.2M = 35m moles
Initial 12.5m 35m 0 0
Final 0 22.5m 12.5m
Hence the final pH will be equal to 4.504