In: Statistics and Probability
For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.
In a combined study of northern pike, cutthroat trout, rainbow
trout, and lake trout, it was found that 28 out of 854 fish died
when caught and released using barbless hooks on flies or lures.
All hooks were removed from the fish.
(a) Let p represent the proportion of all pike and trout that die
(i.e., p is the mortality rate) when caught and released using
barbless hooks. Find a point estimate for p. (Round your answer to
four decimal places.)
(b) Find a 99% confidence interval for p. (Round your answers to
three decimal places.)
lower limit
upper limit
Give a brief explanation of the meaning of the interval.
1% of the confidence intervals created using this method would
include the true catch-and-release mortality rate.
99% of all confidence intervals would include the true
catch-and-release mortality rate.
1% of all confidence intervals would include the true
catch-and-release mortality rate.
99% of the confidence intervals created using this method would
include the true catch-and-release mortality rate.
(c) Is the normal approximation to the binomial justified in
this problem? Explain.
No; np > 5 and nq < 5.
No; np < 5 and nq > 5.
Yes; np > 5 and nq > 5.
Yes; np < 5 and nq < 5.
Answer:
Solution :
Given that,
n = 854
x = 28
Point estimate = sample proportion = = x / n = 28/854 = 0.0327
1 - = 1-0.0327 = 0.9673
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 2.576 ( Using z table )
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 2.576 (((0.0327*0.9673) / 854)
E= 0.015
A 99% confidence interval for population proportion p is ,
- E < p < + E
0.0327 - 0.015 < p < 0.0327 + 0.015
0.017 < p < 0.047
The 99% confidence interval for the population proportion p is :lower limit 0.017 upper limit 0.047
99% of the confidence intervals created using this method would include the true catch-and-release mortality rate.
c) Yes; np > 5 and nq > 5.
Is the normal approximation to the binomial it is greater than 5
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