An asteroid, whose mass is 4.90×10-4 times the mass of Earth, revolves in a circular orbit...

An asteroid, whose mass is 4.90×10^-4 times the mass of Earth, revolves in a circular orbit around the Sun at a distance that is 6 times the Earth's distance from the Sun. Calculate the period of revolution of the asteroid.

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What is the ratio of the kinetic energy of the asteroid to the kinetic energy of Earth?

Expert Solution

genius_generous answered 2 years ago

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