How much energy is required to melt a 170 g lead cube at 328 ∘C? Express...

How much energy is required to melt a 170 g lead cube at 328 ∘C?

Express your answer with the appropriate units.

Solutions

Expert Solution

Amount of enery required to change the state of 1 kilogram of a substance is called its specific latent heat.

Amount of energy needed can be calculated by this equation.

Energy(J) = Specific latent heat (J/Kg) * mass (Kg)

The melting point temperatures and latent heat of melting of some substances is shown below.

From this table,let us look at Lead.

At 328⁰C, i.e., at the melting point temperature of lead,its specific latent heat is 23KJ/Kg

Given mass of lead = 170 g

= 170 *10^-3 Kg

Now, Energy required to melt = specific latent heat * mass

= (23 * 10³)J/Kg * (170 * 10^-3)Kg

= 3910 J

Therefore, the energy required to melt a 170 g lead cube at 328⁰C is 3910 Joules.

genius_generous answered 1 year ago

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