Question

in simple C++:

2. Create a structure Fraction which contains a numerator and a denominator then do the following:

a. Write a function void printFraction(Fraction f) which prints out a fraction in the following format; e.g. if the numerator is 2 and the denominator is 5, it will print out 2/5

b. Write a function Fraction mult(Fraction f1, Fraction f2) which returns a new fraction which is the product of f1 and f2.

c. Write a function Fraction add(Fraction f1, Fraction f2) which returns a new fraction which is the sum of f1 and f2. You may simply multiply each fraction by the other’s denominator to find a common denominator; e.g. (3/4)+(5/6) = (3*6/4*6)+(5*4/6*4) = 38/24. You do NOT have to reduce the fractions.

Answer 1

C++ Code :

#include <bits/stdc++.h>
using namespace std;
struct Fraction// name of the structure storing numerator and denominator
{
int n;//numerator
int d;//denominator
};
void printFraction(Fraction f) // this function is to print the fraction in " n / d " form
{
cout<< (f.n) << "/" << (f.d) << "\n"; // "." is used to make a reference to the variable n and d
}
Fraction mult(Fraction f1, Fraction f2)//this function is to multiply the two fractions
{
Fraction f3;//multiplication is n*n / d*d
f3.n = f1.n * f2.n;
f3.d = f1.d * f2.d;
return f3;
}
Fraction add(Fraction f1, Fraction f2)//this function is to add the two fractions
{
Fraction f3;
f3.n = (f1.n * f2.d ) + (f2.n * f1.d);//this is by easy lcm method
f3.d = f1.d * f2.d;
return f3;
}
int main()
{
int a,b;
cout<<"Enter the numerator of a fraction : ";
cin>>a;
cout<<"Enter the denominator of a fraction : ";
cin>>b;
Fraction f;
f.n=a;
f.d=b;
cout<<"The value of fraction is : ";
printFraction(f);
  
Fraction f1;
Fraction f2;

cout<<"Enter the numerator of a fraction 1: ";
cin>>a;
cout<<"Enter the denominator of a fraction 1: ";
cin>>b;

f1.n = a;
f1.d = b;

cout<<"Enter the numerator of a fraction 2: ";
cin>>a;
cout<<"Enter the denominator of a fraction 2: ";
cin>>b;

f2.n = a;
f2.d = b;;
f=mult(f1,f2);//multiply two fraction and store in f
cout<<"The value of fraction after muliplication is : ";
printFraction(f);
  
f=add(f1,f2);//add two fraction and store in f
cout<<"The value of fraction after addition is : ";
printFraction(f);
return 0;
}

The output is also shown here :

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