In: Statistics and Probability
Part 1: The mean daily production of a herd of
cows is assumed to be normally distributed with a mean of 32
liters, and standard deviation of 9 liters.
A) What is the probability that daily production is
between 24.8 and 30.9 liters? Do not round until
you get your your final answer.
Part 2: The mean daily production of a herd of
cows is assumed to be normally distributed with a mean of 31
liters, and standard deviation of 9.8 liters.
A) What is the probability that daily production is
less than 58.7 liters?
Answer= (Round your answer to 4 decimal places.)
B) What is the probability that daily production is
more than 12.7 liters?
Answer= (Round your answer to 4 decimal places.)
Part 3 Company XYZ know that replacement times
for the DVD players it produces are normally distributed with a
mean of 7.7 years and a standard deviation of 1.5 years.
Find the probability that a randomly selected DVD player will have
a replacement time less than 3.8 years?
P(X < 3.8 years) =
Enter your answer accurate to 4 decimal places. Answers obtained
using exact z-scores or z-scores rounded to 3
decimal places are accepted.
If the company wants to provide a warranty so that only 3.2% of the
DVD players will be replaced before the warranty expires, what is
the time length of the warranty?
warranty = years
Solution :
Given that ,
1) mean = = 32
standard deviation = = 9
a) P( 24.8< x <30.9 ) = P[(24.8-32)/9 ) < (x - ) /< (30.9-32) /9 ) ]
= P( -0.80< z < -0.12)
= P(z <-0.12 ) - P(z <-0.80 )
Using standard normal table
= 0.4522- 0.2119 = 0.2403
Probability = 0.2403
2)
mean = =31
standard deviation = =9.8
a) P(x < 58.7 ) = P[(x - ) / < (58.7-31) /9.8 ]
= P(z < 2.83 )
= 0.9977
probability = 0.9977
b)
P(x > 12.7) = 1 - p( x< 12.7 )
=1- p P[(x - ) / < (12.7-31) /9.8 ]
=1- P(z < -1.87 )
= 1 - 0.0307 = 0.9693
probability = 0.9693
3)
mean = = 7.7
standard deviation = =1.5
a) P(x < 3.8 ) = P[(x - ) / < ( 3.8-7.7) /1.5 ]
= P(z < -2.600 )
= 0.0047
probability =0.0047
b) 3.2%
P(Z < z ) = 0.032
z = -1.85
Using z-score formula,
x = z * +
x = -1.85 *1.5 +7.7
x = 4.93
ANSWER = 4.93 Years