Question

In: Chemistry

Water's heat of fusion is 80. cal/g , its specific heat is 1.0calg⋅∘C, and its heat...

Water's heat of fusion is 80. cal/g , its specific heat is 1.0calg⋅∘C, and its heat of vaporization is 540 cal/g . A canister is filled with 340 g of ice and 100. g of liquid water, both at 0 ∘C . The canister is placed in an oven until all the H2O has boiled off and the canister is empty. How much energy in calories was absorbed? Express your answer to two significant figures and include the appropriate units

Solutions

Expert Solution

340 g ice will need = 340 g x 80 cal/g

= 27200 cal heat

360g melted Ice and 100g water to rise to

boiling temperature needs = 440 g x 100 cal/g

                                            = 44000 cal
                                       

To boil off the whole amount need another = 440 g x 540 cal/g

                                                                    = 237600 cal

Total heat needed = 27200 + 44000 + 237600

                              = 308800 cal = 3.1 x 10^5 cal

                              = 308.8 kcal

                              = 3.1 x 10^2 kcal


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