In: Physics
A place-kicker must kick a football from a point 36.0 m (about 40 yards) from the goal. Half the crowd hopes the ball will clear the crossbar, which is 3.05 m high. When kicked, the ball leaves the ground with a speed of 20.2 m/s at an angle of 51.0° to the horizontal.
(a) By how much does the ball clear or fall short (vertically)
of clearing the crossbar? (Enter a negative answer if it falls
short.)
Find the two initial velocity components, and from them and the
equations of motion, determine the time and height when the
football has traveled the required distance measured along the
ground. m
(b) Does the ball approach the crossbar (and cross above or beneath
it) while still rising or while falling?
rising
or falling
Gravitational acceleration = g = -9.81 m/s2
Initial velocity of the ball = V0 = 20.2 m/s
Angle of the initial velocity with the horizontal = =
51o
Initial horizontal velocity = Vx0
Vx0 = VCos
Vx0 = 20.2Cos(51)
Vx0 = 12.71 m/s
Initial vertical velocity = Vy0
Vy0 = VSin
Vy0 = 20.2Sin(51)
Vy0 = 15.7 m/s
Horizontal distance of the crossbar from the ball = R = 36 m
Height of the crossbar = H = 3.05 m
Time taken by the ball to reach the crossbar = T
There is no force acting on the ball in the horizontal direction hence the velocity in the horizontal direction is constant.
R = Vx0T
36 = (12.71)T
T = 2.832 sec
Height of the ball when it reaches the crossbar = h
h = Vy0T + gT2/2
h = (15.7)(2.832) + (-9.81)(2.832)2/2
h = 5.12 m
Height the ball clears the crossbar by = H
H = h - H
H = 5.12 -
3.05
H = 2.07 m
Vertical velocity of the ball when it crosses the crossbar = Vy1
Vy1 = Vy0 + gT
Vy1 = 15.7 + (-9.81)(2.832)
Vy1 = -12.08 m/s
The negative velocity indicates the ball is traveling downwards.
The vertical velocity of the ball is negative when it crosses the crossbar hence the ball is falling when the ball crosses the crossbar.
a) The ball clears the crossbar by a distance of 2.07 m
b) The ball approaches the crossbar from above it and is falling when it crosses.