In: Statistics and Probability
The time a student sleeps per night has a distribution with mean 6.15 hours and a standard deviation of 0.5 hours. Find the probability that average sleeping time for a randomly selected sample of 40 students is more than 6.29 hours per night. Answer: (keep 4 decimal places)
Solution :
mean = = 6.15
standard deviation = = 0.5
n = 40
= = 6.15
= / n = 0.5 / 40 = 0.079
P( > 6.29) = 1 - P( < 6.29)
= 1 - P[( - ) / < (6.29 - 6.15) / 0.079 ]
= 1 - P(z < 1.77)
Using z table,
= 1 - 0.9616
= 0.0384