In: Statistics and Probability
If a study shows that the amount of time a student sleeps on any given nights is normally distributed with a mean of 7.2 hours and a standard deviation of 3 hours.
Find the probability of one randomly selected student sleeping less than 8 hours.
X: amount of time a student sleeps on any given nights
X follows normal distribution with mean of 7.2 hours and a standard deviation of 3 hours
probability of one randomly selected student sleeping less than 8 hours = P(X<8)
Z-score for 8 = (8-mean) / standard deviation = (8-7.2)/3 = 0.8/3 = 0.27
From standard normal tables ,
P(Z<0.27) = 0.6064
P(X<8) = P(Z<0.27) = 0.6064
Probability of one randomly selected student sleeping less than 8 hours = P(X<8) = 0.6064
Probability of one randomly selected student sleeping less than 8 hours = 0.6064