Question

Find the distance between the following pair of points

(2,5) , (3,2)

Answer 1

Let P(2,5) and Q(3,2) be the given points,and the line is in straight line.

Here x1=2, y1= 5 and X2 =3 , y2=2

PQ =√(x2-x1)^2 + (y2-y1)^2

         =√(3-2)^2 +(2-5)^2

         =√1^2 + (-3)^2

        =√1+9

       =√10

       Hence the distance between two points is √10 units

Hence the distance between two points PQ is √10 units