In: Statistics and Probability
In planning both market opportunity and production levels, being
able to estimate the size of a market can be important. Suppose a
diaper manufacturer wants to know how many diapers a one-month-old
baby uses during a 24-hour period. To determine this usage, the
manufacturer’s analyst randomly selects 17 parents of
one-month-olds and asks them to keep track of diaper usage for 24
hours. The results are shown. Construct a 99% confidence interval
to estimate the average daily diaper usage of a one-month-old baby.
Assume diaper usage is normally distributed.
11 | 8 | 11 | 9 | 13 | 14 | 13 |
13 | 9 | 13 | 11 | 8 | 11 | 15 |
13 | 7 | 11 |
(Round the intermediate values to 3 decimal places.
Round your answers to 2 decimal places.)
(blank) ≤ μ ≤ (blank)
The sample size is n = 17 . The provided sample data along with the data required to compute the sample mean and sample variance are shown in the table below:
X | X2 | |
11 | 121 | |
8 | 64 | |
11 | 121 | |
9 | 81 | |
13 | 169 | |
14 | 196 | |
13 | 169 | |
13 | 169 | |
9 | 81 | |
13 | 169 | |
11 | 121 | |
8 | 64 | |
11 | 121 | |
15 | 225 | |
13 | 169 | |
7 | 49 | |
11 | 121 | |
Sum = | 190 | 2210 |
The sample mean is computed as follows:
Also, the sample variance is
Therefore, the sample standard deviation s is
The number of degrees of freedom are df = 24 - 1 = 23 , and the significance level is α=0.01.
Based on the provided information, the critical t-value for α=0.01 and df = 23 degrees of freedom is t_c = 2.807
The 99% confidence for the population mean μ is computed using the following expression
Therefore, based on the information provided, the 99 % confidence for the population mean μ is
Ci = (11.176 - 1.332, 11.176 + 1.332)
CI= (9.84, 12.51)