In: Statistics and Probability
A small regional carrier accepted 13 reservations for a
particular flight with 12 seats. 10 reservations went to regular
customers who will arrive for the flight. Each of the remaining
passengers will arrive for the flight with a 46% chance,
independently of each other.
(Report answers accurate to 4 decimal places.)
Find the probability that overbooking occurs.
Find the probability that the flight has empty seats.
Here we have,
A small regional carrier accepted 13 reservations for a particular flight with 12 seats. 10 reservations went to regular customers who will arrive for the flight. Each of the remaining passengers will arrive for the flight with a 46% chance, independently of each other
i.e. for remaining 2 seats there are 3 reservations and passenger will arrive for the flight independently with a 46% chance
Hence here
p=0.46 and n=3
This is Binomial Distribution with parameter n=3 and p=0.46
probability that overbooking occurs means all 3 passenger arrives for 2 seats, i.e.
Thus
probability that overbooking occurs is 0.0973
Now
the probability that the flight has empty seats means 0 or 1 passenger arrive for 2 seats i.e.
Thus
probability that the flight has empty seats is 0.5599