In: Physics
A parallel plate capacitor with plate separation d is connected to a battery. The capacitor is fully charged to Q Coulombs and a voltage of V. (C is the capacitance and U is the stored energy.) Answer the following questions regarding the capacitor charged by a battery.
For each statement below, select True or False.
1. With the capacitor connected to the battery, increasing d increases U.
2. After being disconnected from the battery, inserting a dielectric with κ will decrease V.
3. With the capacitor connected to the battery, decreasing d decreases Q.
4. After being disconnected from the battery, inserting a dielectric with κ will increase U.
5. After being disconnected from the battery, inserting a dielectric with κ will decrease C.
6. After being disconnected from the battery, decreasing d increases C.
1)false.
With the capacitor connected to the battery, increasing d causes C to increases,U decreases.
charge Q is constant .energy stored U=0.5*Q^2/C
where C= εA/d
2)true
After being disconnected from the battery, inserting a dielectric with κ will decrease V.
C = kεA/d, inserting a dielectric k will cause C to increase. Since charge Q is constant, and Q = CV, increasing C causes V to decrease.
3)false
With the capacitor connected to the battery, decreasing d decreases Q
C increases U will increases and Q will increases.
4) false
Charge Q is constant, energy store is U =
(0.5)Q2/C
Since C = kεA/d, inserting dielectric k will cause C to increase.
Since C increases, U then decreases.
5)false
After being disconnected from the battery, inserting a dielectric with κ will decrease C.
Since C = kεA/d, inserting a dielectric k will cause C to increase.
6)false
After being disconnected from the battery, decreasing d increases C.
Since C = εA/d, decreasing d causes C to increase.