Question

In: Statistics and Probability

The following table contains observed frequencies for a sample of 200. Column Variable Row Variable A...

The following table contains observed frequencies for a sample of 200.

Column Variable
Row Variable A B C
P 40 48 45
Q 10 22 35

Test for independence of the row and column variables using a=.05.

Compute the value of the test statistic (to 2 decimals).

The -value is - Select your answer -less than .005between .005 and .01between .01 and .025between .025 and .05between .05 and .10greater than .10

What is your conclusion?

- Select your answer -Cannot reject the assumption that rows and columns are independent

Conclude the row variable and column variable are not independent

Solutions

Expert Solution

the necessary calculation table be:-

row variable A B C total
P observed frequency(Oi) 40 48 45 133
expected frequency(Ei)

(50*133)/200

= 33.25

46.55 53.20
1.3703 0.0452 1.2639
Q observed frequency(Oi) 10 22 35 67
expected frequency(Ei) 16.75 23.45 26.80
2.7201 0.0897 2.5090
column total of observed frequency 50 70 80

hypothesis:-

the row and column variables are independent.

the row and column variables are not independent.

the test statistic be:-

The p-value is :- between 0.01 and 0.025

[ df = (3-1)*(2-1)= 2

fro chi square table for df =2,chi square = 8.00 ]

my conclusion is:-

Conclude the row variable and column variable are not independent.

[ p value < 0.025 < 0.05 (alpha).

so we reject our null hypothesis.]

***in case of doubt, comment below. And if u liked the solution, please like.


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