A microfiltration membrane operating with pure feed of water produces a flux of 0.06 k g ⋅ s − 1 ⋅ m − 2 0.06 kg⋅s−1⋅m−2 when operated with a TMP of 30 k P a 30kPa.

A microfiltration membrane operating with pure feed of water produces a flux of $0.06 k g \cdot s - 1 \cdot m - 2 "> 0.06 k g \cdot s^{- 1} \cdot m^{- 2}$ when operated with a TMP of $30 k P a "> 30 k P a$ . 1. What is the resistance due to the membrane? Specify the units. 2. If operated with a protein-water mixture at a $20 k P a "> 20 k P a$ pressure difference, a flux of $216 \times "> 216 \times$ $10 - 6 k g \cdot s - 1 \cdot m - 2 "> 10^{- 6} k g \cdot s^{- 1} \cdot m^{- 2}$ is measured at steady state. What is the resistance due to cake build-up? Specify the units.

Solutions

Expert Solution

Solution : The general equation is:

1. When pure water is being filtered, the resistance due to cake build up is zero, so solve the equation for $R m' "> R_{m}^{'}$ . Using/assuming water viscosity to be $μ = 1 \times 10 - 3 "> μ = 1 \times 10^{- 3}$ Pa.s, then $R m' = 5 \times 108 m 2 . k g - 1 ">$ R_m'=5×10⁸ m².kg^-1

2. This membrane resistance remains the same when filtering the protein, so solving the general equation gives R_c^'=9.2×10¹⁰m².kg^-1

SUN BUNRA answered 2 years ago

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Question

A microfiltration membrane operating with pure feed of water produces a flux of 0.06 k g ⋅ s − 1 ⋅ m − 2 0.06 kg⋅s−1⋅m−2 when operated with a TMP of 30 k P a 30kPa.

Solutions

Expert Solution

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