Question

In: Physics

1. Which is true about the stopping potential Vstop? It is the amount of energy required...

1. Which is true about the stopping potential V_stop?

It is the amount of energy required to stop an incident photon.

It is the amount of energy required to stop a freed electron.

The product of charge e and V_stop is the amount of energy required to stop an incident photon.

The product of charge e and V_stop is the amount of energy required to stop a freed electron.

2. What happens to the shift in wavelength of the x rays if we increase the mass of the target?

decreases

remains the same

increases

3.

If an electron moves into a region where it then has more potential energy, which is true?

It moves slower and has a smaller angular wavenumber.

It moves faster and has a greater angular wavenumber.

It moves faster and has a smaller angular wavenumber.

It moves slower and has a greater angular wavenumber.

Expert Solution

1.

The amount of potential to be applied to stop a freed electron which has maximum kinetic energy is called Stopping Potential.

If the potential applied is V, then the work done to stop the electron is given by:

Therefore this is the energy required to stop the freed electron. So, the forth statement is true.

2.

The minimum wavelength of continuous X rays is given by the formula:

h is plank constant

c is speed of light

e is charge of electron

V is the potential to which the electrons are accelerated.

As we can see from the formula that the wavelength of X rays does not depend on mass of the target metal. Therefore there will not be any change in wavelength. Therefore, second option is correct.

3.

Since electron has negative charge. When left free it will accelerate opposite to the direction of electric field. And Electric field direction will be from high potential to low potential. But if the electron moved to region where it has more potential, that means it is moving along electric field, which will make the electron slow down.

Since the electron slows down, its de Broglie wavelength will increase, which inturn decreases the angular wave number.

Formula for de Broglie wavelength is:

Formula for angular wave number is:

Therefore first option is correct.

genius_generous answered 1 month ago

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