1) The half-life for the first-order decay of 14C is 5730 years. How long will it...

1) The half-life for the first-order decay of 14C is 5730 years. How long will it take for a sample to decay to just 10% of it’s initial amount?

Expert Solution

Half life for the first order decay of 14C i.e t_1/2 = 5730Y

t_1/2= 0.693/λ

λ = 0.693/5730

λ = 0.0001

from first order reaction λ = 2.303/t log a/a-x

time taken for the completion of the 10% of the reaction

t = 2.303/0.0001 log 100/90

t = 23030 log 10/9

t = 1053.7Y

queen_honey_blossom answered 1 month ago

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