In: Physics
Light with a wavelength of 616 nm passes through a slit 7.74 μm wide and falls on a screen 1.90 m away.
Q : Find the linear distance on the screen from the central bright fringe to the first bright fringe above it.
Distanced from source to screen D = 1.90 m,
Wavelength of light used λ =616 nm
= 616 x 10-9 m and
Slit width d = 7.74 μm
= 7.74 x 10-6 m.
Condition for 1 st bright fringe d sinθ = 1.5λ
For small angles sin θ= y / D
From this d y / D = 1.5 λ
Required linear distance y = 1.5 λD / d
= 1.5(616 * 10-9 m)(1.90 m)/( 7.74 * 10-6 m.)
= 0.22682 m
= 22.68 cm