Question

Write a Python program to simulate a very simple game of 21
•Greet the user.
•Deal the user a card and display the card with an appropriate message.
•Deal the user another card and display the card
.•Ask the user if they would like a third card. If so, deal them another card and display the value with an appropriate message.
•Generate a random number between 10 and 21 representing the dealer’s hand. Display this value with an appropriate message.
•If the user’s total is greater than the dealer’s hand and the user’s total is NOT greater than 21, the user wins, otherwise the dealer wins. Display the player’s and the dealer’s totals along with an appropriate message indicating who won.

Answer 1

code:-

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import random
sum=0;
print("WELCOME TO THE GAME OF 21\n");
d=random.randint(0,21);
print("HERE IS YOUR 1st CARD:-");
print(d);
sum=sum+d;
d=random.randint(0,21);
print("HERE IS YOUR 2nd CARD:-");
print(d);
sum=sum+d;
user = input("WANT A THIRD CARD THEN ENTER yes ELSE ENTER no:\n");
if user == "yes" :
    d=random.randint(0,21)
    sum=sum+d
    print("\nHERE IS YOUR 3rd CARD:-")
    print(d)
    print("\n");
else:
    print("\n");
deal=random.randint(10,21);
if sum>deal and sum<21:
    print("USER WON\n");
else:
    print("DEALER WON\n");
print("DEALERS HAND NUMBER:-");
print(deal);
print("USERS TOTAL NUMBER:-");
print(sum);

output

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