In: Biology
What would be the frequency of AABBCC individuals from a mating of two AaBbCc individuals?
Select one:
a. 1/64
b. 1/32
c. 1/8
d. 3/16
e. 1/4
f. 1/16
The correct answer is option (a) 1/64.
AaBbCc individuals would have gametes as ABC, ABc, AbC, aBC, Abc, aBC, abC, abc. When a punnet square is worked out, the ratio comes out to be 27:9:9:9:3:3:1.
To calculate frequency of AABBCC, we need to divide number of genotypes with AABBCC/ Total number of individuals.
As shown in attached figure, there is only 1 individual with this genotype out of 64. So, frequency will be 1/64.