Question

If 6.00 moles of a monatomic ideal gas at a temperature of 260 K are expanded isothermally from a volume of 1.07 L to a volume of 4.61 L .

Calculate the work done by the gas.

Calculate the heat flow into or out of the gas.

If the number of moles is doubled, by what factors do your answers to parts A and B change?

Answer 1

monatomic ideal gas n = 6.0 mole

Temperature T = 260 K

Initial volume V1 = 1.07 L

Final volume V2 = 4.61 L

i. The work done by the gas W =2.303nRT log(V2/V1)

                                              = 2.303x6x260x8.314x log(4.61/1.07)

                                             W = 18946. 76 J

ii. the heat flow into or out of the gas in isothermal process is dQ =dW

                                          i.e dQ = 18946. 76 J

iii. the number of moles is doubled i.e n' = 2n = 2x6 = 12

Wordone W' = 2W

increased by factors 2 from parts A and B change

P =