Question

In: Physics

An object is placed 68cm from a screen 1. At what point from the object should...

An object is placed 68cm from a screen

1. At what point from the object should a converging lens with a focal length of 17cm be placed so that it will produce a sharp image on the screen? (in cm from the object)

2. What is the image's magnification?

Expert Solution

The distance from the screen to the object is,]

u + v = 68

The thin lens equation is,

1/f = 1/u +1/v

f = uv/(u+v)

= uv/68

Then, we get

uv = 68*f = 68*17 = 1156

sop (u-v)^2 = (u+v)^2 -4uv

(u-v)^2 = 68*68-(4*1156)

u -v = 0

u =v

as u+v = 68

2u = 68

= 34 cm

and v = 34 cm

magnification m = -v/u = -1

genius_generous answered 1 month ago

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