Question

In: Physics

How to slove: Simple Harmonic Motion Amplitude = 10ᵒ m = 100.0 g Length =...

How to slove: Simple Harmonic Motion

Amplitude = 10ᵒ

m = 100.0 g

Length =

1.000 m

0.850 m

0.700 m

0.550 m

0.400 m

0.250 m

0.100 m

Trial

t₁₀ (s)

T (s)

t₁₀ (s)

T (s)

t₁₀ (s)

T (s)

t₁₀ (s)

T (s)

t₁₀ (s)

T (s)

t₁₀ (s)

T (s)

t₁₀ (s)

T (s)

Average:

Solutions

Expert Solution

We have plotted scatter graph of Period square vs. Length of string and its linear best-fit line. The Y-values represent the period square and X-values represent the length of string .

The linear best-fit line equation is:

The slope of the best-fit line equation is:

The Y-intercept of the best-fit line equation is:

Therefore, the best-fit line equation is:

We know that the period of the pendulum is expressed as:

Equating equation (1) and (2) gives the slope of the linear best-fit line is equal to term .

Therefore, the experimental value of the gravitational acceleration is .

The percentage difference between experimental value of the gravitational acceleration and theoretical value of the gravitational acceleration is calculated as:

genius_generous answered 1 year ago

Next > < Previous

Related Solutions

particle is in simple harmonic motion along the x axis. The amplitude of the motion is...

particle is in simple harmonic motion along the x axis. The amplitude of the motion is xm. When it is at x = x1, its kinetic energy is K = 5 J and its potential energy (measured with U = 0 at x = 0) is U = 3 J. When it is at x = −1 2x1, the kinetic and potential energies are: A. K = 5 J and U = 3J B. K = 5 J and U...

A bolt of mass 2.08×10?2 kg moves with simple harmonic motion that has an amplitude of...

A bolt of mass 2.08×10?2 kg moves with simple harmonic motion that has an amplitude of 0.243 m and a period of 1.480 s. The displacement of the bolt is 0.243 m when t = 0. (a) Find the displacement of the bolt at time t = 0.508 s. (b) Find the magnitude of the force acting on the bolt at time t = 0.508 s. (c) What is the minimum time required for the bolt to move from its...

Two particles oscillate in simple harmonic motion along a common straight-line segment of length 0.73 m....

Two particles oscillate in simple harmonic motion along a common straight-line segment of length 0.73 m. Each particle has a period of 3.8 s, but they differ in phase by π/8 rad. (a) How far apart are they 1.2 s after the lagging particle leaves one end of the path? (b) Are they then moving in the same direction, toward each other, or away from each other?

A 323 g object is attached to a spring and executes simple harmonic motion with a...

A 323 g object is attached to a spring and executes simple harmonic motion with a period of 0.210 s. If the total energy of the system is 6.70 J. (a) Find the maximum speed of the object. m/s (b) Find the force constant of the spring. N/m (c) Find the amplitude of the motion. mA 323 g object is attached to a spring and executes simple harmonic motion with a period of 0.210 s. If the total energy of...

Write a discussion and conclusion for simple harmonic motion.

Which of the following statements are correct? A. All oscillatory motion is Simple Harmonic Motion. B....

Which of the following statements are correct? A. All oscillatory motion is Simple Harmonic Motion. B. Simple Harmonic motion is a special case of oscillatory motion. C. Oscillatory motion is a special case of Simple Harmonic motion. D. Oscillatory motion cannot be Simple Harmonic motion Which of the following statements is correct? A. In simple harmonic motion, kinetic energy is constant. B. In simple harmonic motion, potential energy is constant. C. In simple harmonic motion, the sum of kinetic and...

1) How do we know that an object performs a simple harmonic motion? 2) Is the...

1) How do we know that an object performs a simple harmonic motion? 2) Is the movement of a pendulum a simple harmonic movement? Explain 3) Are there other types of pendulums that perform a MAS? Explain each

A particle executes simple harmonic motion, such that at a given time, it is at ?A/3...

A particle executes simple harmonic motion, such that at a given time, it is at ?A/3 moving in towards equilibrium. 0.7seconds later, it is at x=0.9A moving towards equilibrium. Find the angular frequency of the particle, if it passes through equilibrium once between the two occurrences. Repeat the above, with the particle passing through equilibrium 5times between the two occurrences.

We have a simple harmonic motion that is described by the equation: ? (?) = 0.82cos...

We have a simple harmonic motion that is described by the equation: ? (?) = 0.82cos (0.4? + 0.2) Determine the equation of v (t) and a (t).

Two harmonic waves of pulsation m and amplitude a overlap at a point P. It is...

Two harmonic waves of pulsation m and amplitude a overlap at a point P. It is observed that also the resulting wave has amplitude equal to a. > Calculate the phase shift Δφ between the two waves; > Calculate the phase shift of the resulting wave with respect to the original wave it has minor initial phase. If the phase shift of the two harmonics is 180 °, how much the resulting wave amplitude would become? data: 1. amplitude of...

Subjects