Question

For a given two-dimensional array in C as follows (Each int-type element occupies 4 bytes of memory)

int A[8][16]; 

If the address of A[1][4] is 0x0FFA0040, what is the memory address of A[2][6]?

Answer 1

A[1][4] is 0x0FFA0040 our address starts from here Each int-type element occupies 4 bytes of memory so we hace to add 4 bytes conitues untill reach A[2][6]
A[1][5] is 0x0FFA0044 add 4 bytes we get this
A[1][6] is 0x0FFA0048 add 4 bytes we get this
A[1][7] is 0x0FFA004c now add 4 bytes to 8 it will 12 in decimal but here address in hex so it is C
A[1][8] is 0x0FFA0050
A[1][9] is 0x0FFA0054
A[1][10] is 0x0FFA0058
A[1][11] is 0x0FFA005c
A[1][12] is 0x0FFA0060
A[1][13] is 0x0FFA0064
A[1][14] is 0x0FFA0068
A[1][15] is 0x0FFA006c
A[2][0] is 0x0FFA0070
A[2][1] is 0x0FFA0074
A[2][2] is 0x0FFA0078
A[2][3] is 0x0FFA007c
A[2][4] is 0x0FFA0080
A[2][5] is 0x0FFA0084
A[2][6] is 0x0FFA008c

//if we do this continues we will reach our desied location whose address is 0x0FFA008c

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