In: Mechanical Engineering
Consider that a 1.35 wt% C- 98.65 wt% Fe alloy. Determine the weight fraction of the following.
(a) Proeutectoid Ferrite:
(b) Proeutectoid Cementite:
(c) Pearlite:
(d) Ferrite in Pearlite:
(a) There will be NO Proeutectoid Ferrite as the composition of carbon is 1.35 % which is greater than the eutectoid composition.
(b) Mass/Weight Fraction of Proeutectoid Cementite will be formed. From lever rule as point 1 i.e just above the line of 727 C.
(c) As the Mass fraction of Proeutectide Cementite is 0.099 ; The rest will be Pearlite.
(d) Mass fraction of Ferrite in Pearlite can be found out From lever rule as point 2 i.e just below the line of 727 C.
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