In: Math
Table below shows monthly beer sales at Gordon’s Liquor Store in 2017.
The sales manager had predicted that January 2017 beer sales would be 950.
Month |
Sales |
Jan 2017 |
900 |
Feb |
725 |
Mar |
1000 |
Apr |
800 |
May |
750 |
Jun |
1200 |
Jul |
1000 |
Aug |
1100 |
Sep |
1250 |
Oct |
1050 |
Nov |
1400 |
Dec |
1600 |
Jan 2018 |
?? |
Forecast beer sales needed for January 2018 using the moving average with 3 periods.
Forecast beer sales needed for January 2018 using an exponential smoothing method with α = 0.2 and α = 0.9
What is the best method to forecast the beer sales according to MSE. (moving average with 3 periods, exponential smoothing method with α = 0.2, or exponential smoothing method with α = 0.9)
1)
forecasted beer sales with moving average with 3 period =(1050+1400+1600)/3=1350
2)
for exponential smoothing: next period forecast =previous period actual*alpha+(1-alpha)*previous period forecast |
for alpha =0.2
month | value | forecast | error^2 | |
1 | 900 | |||
2 | 725 | 900.00 | 30625.00 | |
3 | 1000 | 865.00 | 18225.00 | |
4 | 800 | 892.00 | 8464.00 | |
5 | 750 | 873.60 | 15276.96 | |
6 | 1200 | 848.88 | 123285.25 | |
7 | 1000 | 919.10 | 6544.16 | |
8 | 1100 | 935.28 | 27131.62 | |
9 | 1250 | 968.23 | 79396.27 | |
10 | 1050 | 1024.58 | 646.11 | |
11 | 1400 | 1029.66 | 137148.01 | |
12 | 1600 | 1103.73 | 246281.93 | |
13 | 1202.99 | total | 693024.33 | |
average=MSE= | 63002.21 |
forecast for Jan 2018 with alpha=0.2 is 1202.99
with alpha =0.9
month | value | forecast | error^2 | |
1 | 900 | |||
2 | 725 | 900.00 | 30625.00 | |
3 | 1000 | 742.50 | 66306.25 | |
4 | 800 | 974.25 | 30363.06 | |
5 | 750 | 817.43 | 4546.13 | |
6 | 1200 | 756.74 | 196477.21 | |
7 | 1000 | 1155.67 | 24234.47 | |
8 | 1100 | 1015.57 | 7128.86 | |
9 | 1250 | 1091.56 | 25104.27 | |
10 | 1050 | 1234.16 | 33913.31 | |
11 | 1400 | 1068.42 | 109948.24 | |
12 | 1600 | 1366.84 | 54362.86 | |
13 | 1576.68 | total | 583009.66 | |
average=MSE= | 53000.88 |
forecast for Jan 2018 with alpha=0.9 is 1576.68
3)
as MSE is less with alpha= 0.9 , exponential smoothing method with α = 0.9 seems better.