The molar enthalpy of benzene at its normal boiling point (80.09° C) is 30.72 kJ/mol. Assuming...

The molar enthalpy of benzene at its normal boiling point (80.09° C) is 30.72 kJ/mol. Assuming that Δ H of vaporization and Δ S of vaporization stay constant at their values at 80.09° C, calculate the value of ΔG of vaporization at 75.0° C, 80.09° C, and 85.0° C. Interpret these results physically.

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queen_honey_blossom answered 1 year ago

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